(4n-3)(5n^2+4n-4)=0

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Solution for (4n-3)(5n^2+4n-4)=0 equation:


Simplifying
(4n + -3)(5n2 + 4n + -4) = 0

Reorder the terms:
(-3 + 4n)(5n2 + 4n + -4) = 0

Reorder the terms:
(-3 + 4n)(-4 + 4n + 5n2) = 0

Multiply (-3 + 4n) * (-4 + 4n + 5n2)
(-3(-4 + 4n + 5n2) + 4n * (-4 + 4n + 5n2)) = 0
((-4 * -3 + 4n * -3 + 5n2 * -3) + 4n * (-4 + 4n + 5n2)) = 0
((12 + -12n + -15n2) + 4n * (-4 + 4n + 5n2)) = 0
(12 + -12n + -15n2 + (-4 * 4n + 4n * 4n + 5n2 * 4n)) = 0
(12 + -12n + -15n2 + (-16n + 16n2 + 20n3)) = 0

Reorder the terms:
(12 + -12n + -16n + -15n2 + 16n2 + 20n3) = 0

Combine like terms: -12n + -16n = -28n
(12 + -28n + -15n2 + 16n2 + 20n3) = 0

Combine like terms: -15n2 + 16n2 = 1n2
(12 + -28n + 1n2 + 20n3) = 0

Solving
12 + -28n + 1n2 + 20n3 = 0

Solving for variable 'n'.

The solution to this equation could not be determined.

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